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(C) Initially,the object is at $2f$,so the image is formed at $2f$ on the other side (at point $S$).$(i)$ When a parallel-sided glass block is inserte

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Further away from $S$ (Glass block); Further away from $S$ (Converging lens)

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(C) Initially,the object is at $2f$,so the image is formed at $2f$ on the other side (at point $S$).$(i)$ When a parallel-sided glass block is inserted,the light rays shift laterally but remain parallel to their original path. This causes the virtual object for the convex lens to appear closer to the lens. Since the object distance $u$ effectively decreases $(u  2f)$. Thus,the image shifts further away from $S$.(ii) When a converging lens of long focal length is inserted,it makes the rays more convergent before they hit the convex lens. This effectively makes the object appear closer to the convex lens. Consequently,the image distance $v$ increases $(v > 2f)$,shifting the image further away from $S$.

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Two identical glass $(\mu_g = 3/2)$ equiconvex lenses of focal length $f$ each are kept in contact. The space between the two lenses is filled with water $(\mu_w = 4/3).$ The focal length of the combination is

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The dispersive powers of the materials of two lenses forming an achromatic combination are in the ratio of $4:3$. If the effective focal length of the combination is $+60 \ cm$, then the focal lengths of the lenses should be:

Assertion: Two convex lenses joined together cannot produce an achromatic combination.
Reason: The condition for achromatism is $\frac{\omega_1}{f_1} + \frac{\omega_2}{f_2} = 0$,where symbols have their usual meaning.

In which optical instruments is a combination of lenses used?

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